GMAT Question of the day

A number 774958A96B is to be divisible by 8 and 9, the values of A and B, respectively, will be
[1] 7,8
[2] 8,0
[3] 5,8
[4] None





Since the number is divisible by 8, its last 3 digits are divisible by 8 ie, 960 or 968 , so B is either 0. or 8.
Since the number is divisible by 9, the sum of its digits is divisible by 9.
Adding the digits, we get (55 + A + B) is a multiple of 9.
If B = 8, a must be 9, but no such option is given. If B = 0, A = 8.
(A, B) = (8, 0).