[1] 7,8

[2] 8,0

[3] 5,8

[4] None

Since the number is divisible by 8, its last 3 digits are divisible by 8 ie, 960 or 968 , so B is either 0. or 8.

Since the number is divisible by 9, the sum of its digits is divisible by 9.

Adding the digits, we get (55 + A + B) is a multiple of 9.

If B = 8, a must be 9, but no such option is given. If B = 0, A = 8.

(A, B) = (8, 0).