If xy = 1, then what is the value of 2^(x+y)^2 / 2^(x-y)^2

1)8

2)4

3)2

4)16

Answer:

(x+y)^2 =(x^2+y^2+2xy)

(x-y)^2 =(x^2+y^2 - 2xy)

2^(x^2+y^2+2xy)/2^(x^2+y^2 - 2xy)

= 2^(4xy)

= 2^4

= 16

1)8

2)4

3)2

4)16

Answer:

(x+y)^2 =(x^2+y^2+2xy)

(x-y)^2 =(x^2+y^2 - 2xy)

2^(x^2+y^2+2xy)/2^(x^2+y^2 - 2xy)

= 2^(4xy)

= 2^4

= 16