Car A travels at three times the average speed of car B. Car A started to travel at 12:00 Hrs, car B started to travel at 16:00 Hrs. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?
Let the speed of car B be X.
Then speed of car A is 3X.
Car A traveled 3X x 6 hours = 18X Km.
Car B traveled X x 2 hours = 2X Km.
20X=1000 ---> X = 50 Km/h.
The best answer is E.