GMAT Question of the day

A box contains 90 nuts each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg., then the weight of the empty box is :
A)10 kg
B)10.5 kg
C)11 kg
D)11.5 kg
E)None of the above


Total weight of nuts = 90*100 = 9 Kg

Total weight of bolts = 100*150 = 15 Kg

Total weight of box with nuts and bolts = 35.5 Kg
So the Answer is D

GMAT Question of the Day

The value of some stock X changes according to the following method:
At the end of each month her value is doubled but due to commission the stock’s value is decreases by Rs.10. If the value at the beginning of January is Rs.A, what would be her value at the end of February?

(a) 4A – 10.
(b) 4A – 20.
(c) 4A – 30.
(d) 4A – 40.
(e) 4A – 50 .


At the end of January her value is 2A – 10.
At the end of February her value is (2 x (2A – 10) – 10
= 4A – 30).

The best answer is C.

Question of the day

How many digits does the product of 4^15 and 5^29 contain?
A. 12
B. 13
C. 23
D. 30
E. 35

So our aim is to find how many digits will the product of the above numbers have ie ,
4^15 X 5^29
= (2^2)^15 X 5^29
= 2^30 X 5^29
= 2X 2^29 X 5^29
= 2 X (2 X 5)^29
= 2 X 10^29
so the answer is 30 digit number

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