GMAT Question of the Day

In the rectangular solid , the three sides shown have areas 12, 15, and 20,respectively. What is the volume of the solid?

A. 60
B. 120
C. 450
D. 1,800
E. 3,600


Solution :

ab = 12
bc = 15
ac = 20

a=12/b
c=15/b

ac =20

(12*15)/b^2 = 20
20b^2=180
b=3 a=4 c=5
Volume = 3 * 4 * 5 = = 60

hence the answer is A

GMAT Question of the Day

john intended to place a mark 2 1/4 inches from one end of a narrow end 9 1/4 inches long, but he mistakenly placed the mark 2 1/4 inches from the other end. How far, in inches, is his mark from the location where he intended to place it?

A) 7
B)4 3/4
C)2 1/4
D)5
E)5 1/4



Solution

total lenght is 9 1/4 and john need to put the mark at 2 1/4 form the end.

so 9 1/4 - 2 1/4 = 7

That is actual mark should be at 7 inches.

The mark was put in 2 1/4,

so 7- 2 1/4 = 4 3/4

GMAT Question of the day

A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 4, AB = 5 and AC = 11, what is the length of AE?

(a) 21
(b) 26
(c) 30
(d) 18
(e) 16



In order to find the length of AE, find the length of CD and BC first.
BC = AC – AB = 11 – 5 = 6.
BC = 2CD
CD = 3.
AE = 5 + 6 + 3 + 4 = 18.

The answer is D.

GMAT Question of the day

To which of the following shapes the area can’t be calculated if the perimeter is given?

(a) Circle.
(b) An isoceles right triangle.
(c) Rectangle.
(d) A regular Hexagon.
(e) Square.


The perimeter of a rectangle is 2a + 2b.

In order to calculate the area we need to know the multiplication of a x b.

The best answer is C.

GMAT Question of the Day

In a triangle, one side is 6 Cm and another side is 9 Cm. which of the following can be the perimeter of the triangle?

(a) 18.
(b) 25.
(c) 30.
(d) 32.
(e) 34.


The third side of the triangle is larger than 3 (The difference between the other two) and should be smaller than 15 ( The sum of the other two).
The perimeter is between (6+9+3 = 18) and (6+9+15 = 30). The only answer that is in this range is B.

The best answer is B.

GMAT Question of the Day

Alfa, Beta and Gamma are inner angles in a triangle. If Alfa = Beta + Gamma, what can’t be the size of Beta?
(a) 44 degrees.
(b) 45 degrees.
(c) 89 degrees.
(d) 90 degrees.
(e) There isn’t enough data to determine.


If Beta is 90 degrees than Alfa is bigger than 90 and the sum of the angles in the triangle will be bigger than 180 degrees.

The best answer is D.

GMAT Question of the Day

Chandler is building a fence in the following method: He grounds 10 poles, each 10 Cm thick, in 1 meter spaces from each other. He then connects the poles with a barbed wire. What is the total length of the fence?

(a) 11.

(b) 12.

(c) 9.9.

(d) 10.

(e) 13.




The total width of the poles is (10 x 0.1 = 1) meter.

There are 9 spaces between the poles, each 1 meter, so it’s another 9 meters.

The total length is (1 + 9 = 10) meters.



The best answer is D.

GMAT Question of the day

What is the smallest possible radius of a circle such that it is possible to
place 6 points on the circumference with an integer distance between any
two?
(a) 1/π
(b) 2/π
(c) 6/π
(d) 3/π

The smallest radius means the smallest circumference.
The circumference is 2πr.
With six points equidistant with distance between them to be integer,
this integer has to be the smallest, i.e., 1.
Therefore, circumference is 6 units.
Therefore, 2πr = 6 or r = 3/π.

GMAT Question of the day

A cone of radius 14 cm height 15 cm is cut in a plane parallel to its base. If
the area of the circle at the intersection is 154 sqm then what is the height
from the base at which the cone is cut?

(a) 10cm
(b) 5 cm
(c) 15 cm
(d) 7.5 cm

Since area of circle with BC as radius is 154 sqcm
Π(BC)2 = 154
BC = 7 cm.
Triangles ABC and ADE are similar triangles.
AB/AD = BC/DE.

As BC = 7 and DE is 14 cm
BC/DE = 1/2
AB/AD must also be 1/2.
As AD = 15, AB must be 7.5 cm.
hence the answer is D

GMAT Question of the day

The chord RS of length 8 cm , of a circle with center C,cuts one of the
diameter PQ in a point T such that CT=TQ, If RT = 6,then the diameter of
the circle is
(a) 14 cm
(b) 8 cm
(c) 16 cm
(d) None of these

Let radius of the circle be r

PT = 3r/2 and TQ = r/2.
(3r/2) (r/2) = 6 x 2 = 12.
3r2/4 = 12
⇒ r2 = 16.
r = + 4.

Hence the diameter of the circle is 8 cm. But it is impossible to draw a chord of length 8 cm (other than the diameter) in a circle of diameter 8 cm. The circle must be imaginary.

GMAT question of the day

The length and breadth of a square are increased by 30% and 20%
respectively. The area of the rectangle so formed is more than the area of the
square by:

(a) 50%
(b) 56%
(c) 60%
(d) 10%

We can calculate the percentage increase by L+B+LB concept

Increase percentage = 30 + 20 + (30 x 20)/100

=30+20+(600/100)=56%

Hence the answer is B

GMAT Questions

From a circular sheet of paper with a radius of 20 cm, four circles of radius 5cm each are cut out. What is the ratio of the uncut to the cut portion?

[1] 1 : 3

[2] 4 : 1

[3] 3 : 1

[4] 4 : 3


Answer:


The area of the original paper is (pi)(20)2 = 400(pi).

The area of the cut portion is 4 (pi)(5)2 = 100(pi).

Thus the area of the uncut portion is 300(pi).

The required ratio is 300(pi): 100(pi), i.e. 3 : 1.