Tuesday, January 26, 2010
GMAT Question of the day
(A) 24
(B) 30
(C) 48
(D) 54
(E) 72
210 = 2*3*5*7.
So the numbers have to be made of above four digits.
If we take all 4 primes as separate digits, then 4*3*2*1 = 24 different numbers.
We can also make numbers from the digits 6 (2*3), 5 and 7 = 3*2*1 = 6 different numbers so total 30 numbers.
Hence the answer is B
Monday, December 21, 2009
GMAT question of the day
blocks in each heap should be equal to the number of heaps. If the number
of blocks in each heap is increased by 16, what will be the number of heaps?
(a) 32
(b) 48
(c) 36
(d) 34
Since the number of blocks in each heap should be equal to the number of heaps
X^2=2304
so X=48
When the number of blocks in each heap is increased by 16.
2304/64 = 36
Hence the number of heaps is 36 .Answer is C
GMAT question of the day
by 2, 3 or 5 is
(a) 24
(b) 26
(c) 29
(d) None of these
We can find the numbers that are divisble by 2,3 and 5 then we can subtract from total numbers to get the numbers that are not divisible.
No. divisible by 2 ---50
No. divisible by 5 ---20
This includes 10 numbers divisible by 2,hence we need to subtract them as they already included.
No. divisible by 3 ---33
This includes 13 numbers divisible by 2 and 6 numbers divisible by 5,hence we need to subtract them as they already included.
Then the total Nos. = 50+10+14 = 74
No. not divisible by 2, 3 or 5 is 100 – 74 = 26
GMAT Question of the Day
cannot be the ratio of broken mirrors to unbroken mirrors?
(a) 2: 1
(b) 3: 1
(c) 3: 2
(d) 7 : 5
Since the total number of mirrors is mentioned as 12 (Dozen) it has to be completely divisible by the ratio.
Example : 7+5=12 , 3+1=4 ,2+1=3 but not 3+2=5.
Hence the solution is D.
Monday, September 7, 2009
GMAT Question of the day
L.C.M.?
(a) Only one such pair exists
(b) Only two such pairs exist
(c) More than two pairs exist
(d) No such pairs exist
This is a tricky question and I will post the answer in my next post
Friday, July 31, 2009
Question of the day
a) 99
b) 84
c) 72
d) 65
e) 57
The answers can be expressed in simpler terms as follows
a) 99 = 9 * 11
b) 84 = 7 * 12
c) 72 = 8 * 9
d) 65 = 5 * 13
e) 57 = 3 * 19
The question is to find the number which is not a factor of P.
so the option e is the one with multiple having number other than (1-15) ie, 19.
Wednesday, July 22, 2009
GMAT question of the day
what is the least number of pebbles that heap contains ?
1)100
2)875
3)864
4)760
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LCM of 18,27,32 is 864 and LCM would be exactly divisible by all 3.
So to get a reminder of 11 we need to add 11 to 864 = 875
which is also divisible by 25
Monday, January 26, 2009
PREP FOR GMAT: LEAST COMMON MULTIPLE (L.C.M.)
The least common multiple (LCM) of two numbers is the smallest number (not zero) that is a multiple of both.
NOTE :
The HCF and LCM of two nos is given. It is possible to find out the two nos uniquely if
Either the sum or the difference between the two nos is known.
We know HCF X LCM = Product of the nos
Given that A-B or A+B is known.
Thus we have 2 equations and two variables, thus the soln can be uniquely determined.
or LCM/HCF = prime no is known.
Then one of the nos = LCM and the other = HCF.
Two numbers are said to be co primes if their HCF is one.
PREP FOR GMAT: HIGHEST COMMON FACTOR (H.C.F)
A factor of a given number is every number that divides the given number.
Example
16 = 2 x 8, so numbers 2 and 8 are factors of 16.
Also 16 = 16 x 1, so 16 and 1 are factors of 16.
Also 16 = 4 x 4 ,so 4 is a factor of 16
The factors of 10 are 1, 2,4, 8, and 16.
NOTE: Number 1 and the number itself are always factors of any number.
COMMON FACTORS:
When two (or more) numbers have the same factor, that factor is called a common factor.
Example
Factors of 12 are 1, 2, 3, 4, 6, 12.
Factors of 18 are 1, 2, 3, 6, 18.
The common factors of 12 and 18 are 1, 2, 3 and 6.
HIGHEST COMMON FACTOR:
The Highest Common Factor (H.C.F) of two (or more) numbers is the largest number that divides both the numbers. It is also known as G.C.D. (Greatest common divisor)
In other words the H.C.F is the Highest common factors.