A and B ran a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10th of a minute. In the second heat, A gives B a head start
of 144 m and is beaten by 1/30th of a minute. What is B’s speed in m/s?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 20
Race 1 :
ta = tb-6 ( because A beats B by 6 sec)
Race 2 :
Ta = tb+2 ( because A looses to B by 2 sec)
We know D= S * T
Therefore
480/Sa = 432/Sb -6
and
480/Sa = 336/Sb +2
Equating these two equations we get Sb = 12
ta,Sa stand for time taken by A and speed of A resp
Sunday, August 15, 2010
Thursday, August 5, 2010
GMAT Question of the day
To which of the following shapes the area can’t be calculated if the perimeter is given?
(a) Circle.
(b) An isoceles right triangle.
(c) Rectangle.
(d) A regular Hexagon.
(e) Square.
The perimeter of a rectangle is 2a + 2b.
In order to calculate the area we need to know the multiplication of a x b.
The best answer is C.
(a) Circle.
(b) An isoceles right triangle.
(c) Rectangle.
(d) A regular Hexagon.
(e) Square.
The perimeter of a rectangle is 2a + 2b.
In order to calculate the area we need to know the multiplication of a x b.
The best answer is C.
Sunday, August 1, 2010
GMAT Question of the Day
In a triangle, one side is 6 Cm and another side is 9 Cm. which of the following can be the perimeter of the triangle?
(a) 18.
(b) 25.
(c) 30.
(d) 32.
(e) 34.
The third side of the triangle is larger than 3 (The difference between the other two) and should be smaller than 15 ( The sum of the other two).
The perimeter is between (6+9+3 = 18) and (6+9+15 = 30). The only answer that is in this range is B.
The best answer is B.
(a) 18.
(b) 25.
(c) 30.
(d) 32.
(e) 34.
The third side of the triangle is larger than 3 (The difference between the other two) and should be smaller than 15 ( The sum of the other two).
The perimeter is between (6+9+3 = 18) and (6+9+15 = 30). The only answer that is in this range is B.
The best answer is B.
Saturday, July 31, 2010
GMAT Question of the Day
19. If A2 + B2 = 15 and AB = 10, what is the value of the expression
(A – B)2 + (A + B)2 ?
(a) 10.
(b) 20.
(c) 30.
(d) 60.
(e) 70.
(A – B)2 + (A + B)2
=A2 – 2AB + B2 + A2 + 2AB + B2
=2(A2 + B2)
=30.
The best answer is C.
(A – B)2 + (A + B)2 ?
(a) 10.
(b) 20.
(c) 30.
(d) 60.
(e) 70.
(A – B)2 + (A + B)2
=A2 – 2AB + B2 + A2 + 2AB + B2
=2(A2 + B2)
=30.
The best answer is C.
Friday, July 30, 2010
GMAT Question of the Day
The value of some stock X changes according to the following method:
At the end of each month her value is doubled but due to commission the stock’s value is decreases by Rs.10. If the value at the beginning of January is Rs.A, what would be her value at the end of February?
(a) 4A – 10.
(b) 4A – 20.
(c) 4A – 30.
(d) 4A – 40.
(e) 4A – 50 .
At the end of January her value is 2A – 10.
At the end of February her value is (2 x (2A – 10) – 10
= 4A – 30).
The best answer is C.
At the end of each month her value is doubled but due to commission the stock’s value is decreases by Rs.10. If the value at the beginning of January is Rs.A, what would be her value at the end of February?
(a) 4A – 10.
(b) 4A – 20.
(c) 4A – 30.
(d) 4A – 40.
(e) 4A – 50 .
At the end of January her value is 2A – 10.
At the end of February her value is (2 x (2A – 10) – 10
= 4A – 30).
The best answer is C.
Thursday, July 29, 2010
GMAT Question of the Day
A Cell divides into two each round hour. If at a certain round hour, two Cells were placed in a jar, how many Cells will be in the jar in N hours?
(a) 2N
(b) 22N
(c) 2N+1
(d) 2N-1
(e) 2N
Let’s find the number of Cells in the first hours.
After one hour (N=1) there will be 4 Cells.
After two hours (N=2) there will be 8 Cells.
After three hours (N=3) there will be 16 Cells.
Therefore the formula that fits this series is 2N+1.
The best answer is C.
(a) 2N
(b) 22N
(c) 2N+1
(d) 2N-1
(e) 2N
Let’s find the number of Cells in the first hours.
After one hour (N=1) there will be 4 Cells.
After two hours (N=2) there will be 8 Cells.
After three hours (N=3) there will be 16 Cells.
Therefore the formula that fits this series is 2N+1.
The best answer is C.
Wednesday, July 28, 2010
GMAT Question of the Day
Alfa, Beta and Gamma are inner angles in a triangle. If Alfa = Beta + Gamma, what can’t be the size of Beta?
(a) 44 degrees.
(b) 45 degrees.
(c) 89 degrees.
(d) 90 degrees.
(e) There isn’t enough data to determine.
If Beta is 90 degrees than Alfa is bigger than 90 and the sum of the angles in the triangle will be bigger than 180 degrees.
The best answer is D.
(a) 44 degrees.
(b) 45 degrees.
(c) 89 degrees.
(d) 90 degrees.
(e) There isn’t enough data to determine.
If Beta is 90 degrees than Alfa is bigger than 90 and the sum of the angles in the triangle will be bigger than 180 degrees.
The best answer is D.
Wednesday, July 21, 2010
GMAT Question of the day
What is the sum of all the even numbers bigger than (-10) and smaller than 12?
(a) 2.
(b) 10.
(c) 0.
(d) 8.
(e) 4.
This is a series of numbers with a constant difference between them.
The first number is (-8) and the last is (10), there are 10 numbers in total.
Hence its in AP .
The formula for such a series is: ((-8 + 10) x 10)/2 = 10.
The best answer is B.
(a) 2.
(b) 10.
(c) 0.
(d) 8.
(e) 4.
This is a series of numbers with a constant difference between them.
The first number is (-8) and the last is (10), there are 10 numbers in total.
Hence its in AP .
The formula for such a series is: ((-8 + 10) x 10)/2 = 10.
The best answer is B.
Monday, July 19, 2010
GMAT Question of the Day
Chandler is building a fence in the following method: He grounds 10 poles, each 10 Cm thick, in 1 meter spaces from each other. He then connects the poles with a barbed wire. What is the total length of the fence?
(a) 11.
(b) 12.
(c) 9.9.
(d) 10.
(e) 13.
The total width of the poles is (10 x 0.1 = 1) meter.
There are 9 spaces between the poles, each 1 meter, so it’s another 9 meters.
The total length is (1 + 9 = 10) meters.
The best answer is D.
(a) 11.
(b) 12.
(c) 9.9.
(d) 10.
(e) 13.
The total width of the poles is (10 x 0.1 = 1) meter.
There are 9 spaces between the poles, each 1 meter, so it’s another 9 meters.
The total length is (1 + 9 = 10) meters.
The best answer is D.
Sunday, July 18, 2010
GMAT Question of the day
There are 200 cats in Cat-City. Out of the 200, 70 are street cats and the rest are domestic cats. 110 cats are gray, 30 out of the gray cats are domestic ones. How many domestic cats are there which are not gray in Cat-City?
(a) 90.
(b) 80.
(c) 50.
(d) 40.
(e) 25.
Out of 200 cats, 130 are domestic ones.
Out of 110 gray cats, 30 are street cats therefore 80 are grey and domestic ones.
Altogether there are 130 domestic cats, 80 are grey so (130 – 80) = 50 are not grey.
The best answer is C.
(a) 90.
(b) 80.
(c) 50.
(d) 40.
(e) 25.
Out of 200 cats, 130 are domestic ones.
Out of 110 gray cats, 30 are street cats therefore 80 are grey and domestic ones.
Altogether there are 130 domestic cats, 80 are grey so (130 – 80) = 50 are not grey.
The best answer is C.
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